y^2-8y^2+12y=0

Solution for y^2-8y^2+12y=0 equation:

y^2-8y^2+12y=0

We add all the numbers together, and all the variables

-7y^2+12y=0

a = -7; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·(-7)·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*-7}=\frac{-24}{-14}
=1+5/7
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*-7}=\frac{0}{-14}
=0
$